Answer
$a_{12}=32\sqrt 2$
Work Step by Step
$a_n=a_1r^{n-1}$
$a_1=1,~~r=\sqrt 2$
$a_{12}=1(\sqrt 2)^{12-1}=1(\sqrt 2)^{11}=\sqrt {2^{11}}=\sqrt {2^{10}(2)}=2^5\sqrt 2=32\sqrt 2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 29
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