Answer
$$A=4\sqrt{39}$$
Work Step by Step
By Heron's Formula, we know:
$$A=\sqrt{s(s-a)(s-b)(s-c)}$$
Where:
$$s=\frac{a+b+c}{2}$$
Thus, we find:
$$s=\frac{5+11+10}{2}=13 \\ A=\sqrt{13\left(13-5\right)\left(13-11\right)\left(13-10\right)} \\ A=4\sqrt{39}$$