Answer
$$A=10\sqrt{65}$$
Work Step by Step
By Heron's Formula, we know:
$$A=\sqrt{s(s-a)(s-b)(s-c)}$$
Where:
$$s=\frac{a+b+c}{2}$$
Thus, we find:
$$s=\frac{23+15+12}{2}=25 \\ A=\sqrt{25\left(25-23\right)\left(25-15\right)\left(25-12\right)} \\ A=10\sqrt{65}$$