Chapter 13, Trigonometric Ratios and Functions - 13.6 Apply the Law of Cosines - 13.6 Exercises - Skill Practice - Page 892: 20

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We are given $a, c, b$. Use law of cosines to find $c$: $$b^2=a^2+c^2-2ac\cos B\\ \cos B=\frac{b^2-a^2-c^2}{-2ac}\\\arccos (\cos B)=\arccos\frac{29^2-17^2-14^2}{-2\times17\times14}\\ B \approx 138.4^\circ$$ Hence, the correct answer is D.