Answer
$2.224MeV$
Work Step by Step
We can find the required energy as follows:
First we find the mass of $H^1_1+n^1_0$
$m_i=1.007825u+1.008665u=2.016490u$
and the mass of $H^2_1$ is
$m_f=2.014102u$
$\Delta m=2.014102u-2.016490u=-0.002388u$
Now $E=\Delta mc^2$
We plug in the known values to obtain:
$E=0.002388u(\frac{931.5MeV/c^2}{1u})c^2$
$E=2.224MeV$
