Answer
$78s$
Work Step by Step
We can find the required half-life as follows:
$T_{\frac{1}{2}}=\frac{\ln 2}{\lambda}$
We plug in the known values to obtain:
$T_{\frac{1}{2}}=\frac{\ln 2}{8.9\times 10^{-3}}$
$T_{\frac{1}{2}}=78s$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 32 - Nuclear Physics and Nuclear Radiation - Problems and Conceptual Exercises - Page 1153: 30
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