Answer
$5.4\times 10^{18}s^{-1}$
Work Step by Step
We know that
$R=\frac{P}{E_U}$
We plug in the known values to obtain:
$R=\frac{150\times 10^6W}{173eV}(\frac{eV}{1.6\times 10^{-19}J})$
$R=5.4\times 10^{18}s^{-1}$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 32 - Nuclear Physics and Nuclear Radiation - Problems and Conceptual Exercises - Page 1153: 52
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