Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 36 - Diffraction - Problems - Page 1113: 69

Answer

$d=0.26nm$

Work Step by Step

We know that: $d=\frac{m\lambda}{2sin\theta}$ We plug in the known values to obtain: $d=\frac{2(0.12\times 10^{-9})}{2sin(28^{\circ})}=0.26nm$
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