Answer
$\lambda_A=0.13nm$
Work Step by Step
We know that:
$\lambda_A=2dsin\theta_1$
We plug in the known values to obtain:
$\lambda_A=2(1.7\times 10^2pm)(sin 23^{\circ})=1.3\times 10^2pm=0.13nm$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 36 - Diffraction - Problems - Page 1113: 65b
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