Answer
$\lambda=39.8pm$
Work Step by Step
We know that;
$\lambda=2dsin\theta$
We plug in the known values to obtain:
$\lambda=2(39.8pm)(sin30^{\circ})=39.8pm$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 36 - Diffraction - Problems - Page 1113: 66
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