Answer
$\theta_{min}=2.9^{\circ}$
Work Step by Step
We know that:
$\theta_{min}=sin^{-1}(\frac{m\lambda}{2d})$
We plug in the known values to obtain:
$\theta_{min}=sin^{-1}{\frac{1(30pm)}{2(0.30\times 10^{30}pm)}}=2.9^{\circ}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 36 - Diffraction - Problems - Page 1113: 64
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