Answer
$d=0.17nm$
Work Step by Step
We know that;
$d=\frac{3\lambda_B}{2sin\theta_2}$
We plug in the known values to obtain:
$d=\frac{3(97pm)}{2sin60^{\circ}}=1.7\times 10^2pm=0.17nm$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 36 - Diffraction - Problems - Page 1113: 65a
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