Answer
$d=10\mu m$
Work Step by Step
We know that:
$d=\frac{m\lambda_{avg}}{sin\theta}$
We plug in the known values to obtain:
$d=\frac{3(589.3nm)}{sin10^{\circ}}$
$d=1.0\times10^4nm=10\times 10^{-6}=10\mu m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 36 - Diffraction - Problems - Page 1113: 61a
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