Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 36 - Diffraction - Problems - Page 1113: 58a

Answer

$\Delta \lambda=56pm$

Work Step by Step

We know that: $N=\frac{\lambda}{\Delta \lambda m}$ This can be rearranged as: $\Delta \lambda=\frac{\lambda }{N m}$ We plug in the known values to obtain: $\Delta \lambda=\frac{500 nm}{600\times 5.0(3)}=0.056nm=56pm$
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