Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 5 - Exercises - Page 240: 42

Answer

$$T = 360 \space K$$

Work Step by Step

1. According to the Ideal Gas Law: $$T = \frac{PV}{nR} = \frac{( 1.3 \space atm )( 11.8 \space L )}{( 0.52 \space mol)( 0.08206 \space atm \space L \space mol^{-1} \space K^{-1} )}$$ $$T = 360 \space K$$
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