Answer
$$P = 1.69 \space atm $$
Work Step by Step
$ O_2 $ : ( 16.00 $\times$ 2 )= 32.00 g/mol
- Using the molar mass as a conversion factor, find the amount in moles:
$$ 32.7 \space g \times \frac{1 \space mole}{ 32.00 \space g} = 1.02 \space moles$$
1. According to the Ideal Gas Law:
$$P = \frac{nRT}{V} = \frac{( 1.02 \space mol)( 0.08206 \space atm \space L \space mol^{-1} \space K^{-1} )( 302 \space K)}{ 15.0 \space L }$$
$$P = 1.69 \space atm $$
