Answer
1.65 atm
Work Step by Step
We have,$ P_{1} V_{1} = P_{2} V_{2} $ (combined gas equation)
We are required to find: $P_{2}$ (final pressure)
Therefore,
(13.9) (1.22) = (10.3) $P_{2}$
$P_{2}$ = $\frac{(13.9)(1.22)}{(10.3)}$
$P_{2}$ = 1.65 atm
