Answer
420. mL
Work Step by Step
$n_{1}$ = 0.553 mol
$V_{1}$ = 253 mL
$n_{2}$ = (0.553+0.365) mol = 0.918 mol
According to Avogadro law,
$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$
Or $V_{2}$ = $\frac{V_{1}\times n_{2}}{n_{1}}= \frac{253mL\times0.918mol}{0.553mol}$ = 420. mL
