Answer
4.22 L
Work Step by Step
$n_{1}$ = 0.158 mol
$V_{1}$ = 2.46 L
$n_{2}$ = (0.158+0.113) mol = 0.271 mol
According to Avogadro law,
$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$
Or $V_{2}$ = $\frac{V_{1}\times n_{2}}{n_{1}}= \frac{2.46L\times0.271mol}{0.158mol}$ = 4.22 L
