Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 5 - Exercises - Page 240: 39

Answer

$$P = 1.16 \space atm $$

Work Step by Step

1. According to the Ideal Gas Law: $$P = \frac{nRT}{V} = \frac{( 0.448 \space mol)( 0.08206 \space atm \space L \space mol^{-1} \space K^{-1} )( 315 \space K)}{ 10.0 \space L }$$ $$P = 1.16 \space atm $$
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