Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 5 - Exercises - Page 240: 25

Answer

a. $$ 0.832 \space atm$$ b. $$ 632 \space mmHg$$ c. $$ 12.2 \space psi$$ d.$$ 8.43 \times 10^{4} \space Pa$$

Work Step by Step

a. $$ 24.9 \space in Hg \times \frac{1 \space atm}{29.92 \space in Hg} = 0.832 \space atm$$ b. $$ 24.9 \space in Hg \times \frac{1 \space atm}{29.92 \space in Hg} \times \frac{760 \space mmHg}{1 \space atm} = 632 \space mmHg$$ c. $$ 24.9 \space in Hg \times \frac{1 \space atm}{29.92 \space in Hg} \times \frac{14.7 \space psi}{1 \space atm} = 12.2 \space psi$$ d.$$ 24.9 \space in Hg \times \frac{1 \space atm}{29.92 \space in Hg} \times \frac{101325 \space Pa}{1 \space atm} = 8.43 \times 10^{4} \space Pa$$
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