Answer
$ K_{sp} (MX) = (1.07 \times 10^{-21})$
Work Step by Step
1. Write the $K_{sp}$ expression:
$ MX(s) \lt -- \gt 1M^{n+}(aq) + 1X^{n-}(aq)$
$ K_{sp} = [M^{n+}]^ 1[X^{n-}]^ 1$
2. Determine the ions concentrations:
$[M^{n+}] = [MX] * 1 = [3.27 \times 10^{-11}] * 1 = 3.27 \times 10^{-11}$
$[X^{n-}] = [MX] * 1 = 3.27 \times 10^{-11}$
3. Calculate the $K_{sp}$:
$ K_{sp} = (3.27 \times 10^{-11})^ 1 \times (3.27 \times 10^{-11})^ 1$
$ K_{sp} = (3.27 \times 10^{-11}) \times (3.27 \times 10^{-11})$
$ K_{sp} = (1.07 \times 10^{-21})$
