Answer
Balanced equation:
$ CaC{O_3}(s) \lt -- \gt Ca^{2+}(aq) + C{O_3}^{2-}(aq)$
$K_{sp}$ expression:
$K_{sp} = [Ca^{2+}] \times [C{O_3}^{2-}]$
Work Step by Step
1. Identify the ions in the compound:
$Ca^{2+}$ and $C{O_3}^{2-}$
2. Write the dissociation equation, where the solid ionic compound produces its ions in the water:
$ CaC{O_3}(s) \lt -- \gt Ca^{2+}(aq) + C{O_3}^{2-}(aq)$
Balance the equation:
$1 CaC{O_3}(s) \lt -- \gt 1 Ca^{2+}(aq) + 1 C{O_3}^{2-}(aq)$
3. To get the $K_{sp}$ expression, multiply the ions concentrations, where their balancing coefficients are the exponents of the molarities.
$K_{sp} = [Ca^{2+}]^1 \times [C{O_3}^{2-}]^1$
$K_{sp} = [Ca^{2+}] \times [C{O_3}^{2-}]$
