Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 16 - Sections 16.1-16.8 - Exercises - Problems by Topic - Page 804: 39a

Answer

$pH = 7.60$

Work Step by Step

1. Calculate the pKa Value $pKa = -log(Ka)$ $pKa = -log( 2.9 \times 10^{- 8})$ $pKa = 7.54$ 2. Using the Henderson–Hasselbalch equation: $pH = pKa + log(\frac{[Base]}{[Acid]})$ $pH = 7.54 + log(\frac{0.155}{0.135})$ $pH = 7.54 + log(1.147)$ $pH = 7.54 + 0.06$ $pH = 7.60$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.