Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Review Exercises - Page 249: 64

Answer

$sin^3~\theta = sin~\theta~-cos^2~\theta~sin~\theta$

Work Step by Step

$sin^3~\theta = sin~\theta~sin^2~\theta$ $sin^3~\theta = sin~\theta~(1-cos^2~\theta)$ $sin^3~\theta = sin~\theta~-cos^2~\theta~sin~\theta$
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