Answer
$sin^2~x-sin^2~y = cos^2~y-cos^2~x$
Work Step by Step
$sin^2~x-sin^2~y = (1-cos^2~x)-(1-cos^2~y)$
$sin^2~x-sin^2~y = cos^2~y-cos^2~x$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 5 - Review Exercises - Page 249: 49
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
