Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 418: 62

Answer

$-\dfrac{\sqrt{2}}{2}$

Work Step by Step

The sine is an odd function so $\sin{(-\theta)} = - \sin{\theta}$ Thus, $\sin{(-135 ^{\circ})} = -\sin{(135^{\circ})}$ Due to symmetry of the unit circle $\sin{(135^{\circ})} = \sin{(45^{\circ})}$ Hence, $\sin{(-135 ^{\circ})} = -\sin{(45^{\circ})} =\boxed{-\dfrac{\sqrt{2}}{2}}$
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