Answer
$\text{Quadrant II}$
Work Step by Step
$P= (x,y) \text{ is the point on the unit circle corresponding to } \theta$
We have $\sin{\theta} = y>0 \text{ and } \cos{\theta} = x<0$.
Since points in Quadrant II have $y>0 \text{ and } x<0$, then $\theta \in \text{Quadrant II}$.
