Answer
$\text{Quadrant I}$
Work Step by Step
$P= (x,y) \text{ is the point on the unit circle corresponding to } \theta$
We have:
$\cos{\theta} = x>0 $
$\tan{\theta} = \dfrac{y}{x} >0$
Since $x\gt0$ and $\tan{\theta}\gt0$, then $y\gt 0$.
Note that points in Quadrant I have $y>0 \text{ and } x>0$.
Thusm $\theta \in \text{Quadrant I}$
