Answer
$ f^{-1}(x)=\frac{4}{x}$
See graph.
Work Step by Step
Step 1. $f(x)=\frac{4}{x}\Longrightarrow y=\frac{4}{x} \Longrightarrow x=\frac{4}{y}, \Longrightarrow y=\frac{4}{x}\Longrightarrow f^{-1}(x)=\frac{4}{x}$
Step 2. Check $f( f^{-1}(x))=\frac{4}{\frac{4}{x}}=x$ and $f^{-1}(f(x))=\frac{4}{\frac{4}{x}} =x$
Step 3. See graph for both $f$ and $f^{-1}$.