Answer
$f^{-1}(x)=\sqrt[3] {x+1} $
See graph.
Work Step by Step
Step 1. $f(x)=x^3-1 \Longrightarrow y=x^3-1 \Longrightarrow x=y^3-1 \Longrightarrow y=\sqrt[3] {x+1} \Longrightarrow f^{-1}(x)=\sqrt[3] {x+1} $
Step 2. Check $f( f^{-1}(x))=(\sqrt[3] {x+1} )^3-1=x$ and $f^{-1}(f(x))=\sqrt[3] {(x^3-1)+1} =x$
Step 3. See graph for both $f$ and $f^{-1}$.