Answer
$f^{-1}(x)=-\frac{1}{3}(x-1)$
See graph.
Work Step by Step
Step 1. $f(x)=1-3x \Longrightarrow y=1-3x \Longrightarrow x=1-3y \Longrightarrow y=-\frac{1}{3}(x-1) \Longrightarrow f^{-1}(x)=-\frac{1}{3}(x-1)$
Step 2. Check $f( f^{-1}(x))=1-3(-\frac{1}{3}(x-1))=x$ and $f^{-1}(f(x))=-\frac{1}{3}((1-3x)-1)=x$
Step 3. See graph for both $f$ and $f^{-1}$.