Answer
$f^{-1}(x)=\frac{1}{4}(x-2) $
See graph.
Work Step by Step
Step 1. $f(x)=4x+2 \Longrightarrow y=4x+2 \Longrightarrow x=4y+2 \Longrightarrow y=\frac{1}{4}(x-2) \Longrightarrow f^{-1}(x)=\frac{1}{4}(x-2) $
Step 2. Check $f( f^{-1}(x))=4(\frac{1}{4}(x-2))+2=x$ and $f^{-1}(f(x))=\frac{1}{4}((4x+2)-2)=x$
Step 3. See graph for both $f$ and $f^{-1}$.