Answer
$f^{-1}(x)=\sqrt[3] {x-1} $
See graph.
Work Step by Step
Step 1. $f(x)=x^3+1 \Longrightarrow y=x^3+1 \Longrightarrow x=y^3+1 \Longrightarrow y=\sqrt[3] {x-1} \Longrightarrow f^{-1}(x)=\sqrt[3] {x-1} $
Step 2. Check $f( f^{-1}(x))=(\sqrt[3] {x-1} )^3+1=x$ and $f^{-1}(f(x))=\sqrt[3] {(x^3+1)-1} =x$
Step 3. See graph for both $f$ and $f^{-1}$.