Answer
$\frac{3}{x-3}$
Work Step by Step
By factoring both the denominator and numerator and canceling out the common factors, we have
$$
\frac{3x+9}{x^2-9}=\frac{3(x+3)}{(x-3)(x+3)}=\frac{3}{x-3}
.$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A53: 5
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