Answer
$\dfrac{3x-2}{x-3}, x \ne3$
Work Step by Step
Since the denominators are the same, we have
$$
\frac{x+1}{x-3}+\frac{2x-3}{x-3}=\frac{x+1+2x-3}{x-3}=\frac{3x-2}{x-3}
$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A53: 39
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