Answer
$ \dfrac{8}{3x}$
Work Step by Step
By factoring both the denominator and numerator of each rational function and cancelling the common factors, we have
$$
\frac{4x-8}{-3x}\cdot \frac{12}{12-6x} = \frac{4(x-2)}{-3x}\cdot \frac{12}{-6(x-2)}\\
= \frac{8}{3x}
.$$
