Answer
$\dfrac{3}{5x}$
Work Step by Step
By factoring both the denominator and numerator of each rational function and cancelling the common factors, we have
$$
\frac{6x-27}{5x}\frac{2}{4x-18}=\frac{3(2x-9)}{5x}\frac{2}{2(2x-9)}=\frac{3}{5x}
.$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A53: 22
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