Answer
$\dfrac{(x-2)(x+2)}{2x-3}$
Work Step by Step
Since the denominators are the same, we have
$$
\frac{x^2}{2x-3}-\frac{4}{2x-3}=\frac{x^2-4}{2x-3}=\frac{(x-2)(x+2)}{2x-3}
$$
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