Answer
$\dfrac{4x-5}{3x+4},x \ne -\dfrac{4}{3}$
Work Step by Step
Since the denominators are the same, we have
$$
\frac{5x-4}{3x+4}-\frac{x+1}{3x+4}=\frac{5x-4-x-1}{3x+4}=\frac{4x-5}{3x+4}
$$
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