Answer
$-\frac{\sqrt 3}{2},\frac{1}{2},-\sqrt 3$
Work Step by Step
Use the figure given in the exercise, we have $sin\theta=\frac{-\sqrt 3}{\sqrt {(1)^2+3}}=-\frac{\sqrt 3}{2}$, $cos\theta=\frac{1}{\sqrt {(1)^2+3}}=\frac{1}{2}$, and $tan\theta=\frac{-\sqrt 3}{1}=-\sqrt 3$
