Answer
$\sin A=\frac{20}{29}$
$\csc A=\frac{29}{20}$
$\cos A=\frac{21}{29}$
$\sec A=\frac{29}{21}$
$\tan A=\frac{20}{21}$
$\cot A=\frac{21}{20}$
Work Step by Step
$\sin A=\frac{\text{opposite side}}{\text{hypotenuse}}=\frac{40}{58}=\frac{20}{29}$
$\csc A=\frac{1}{\sin A}=\frac{29}{20}$
$\cos A=\frac{\text{adjacent side}}{\text{hypotenuse}}=\frac{42}{58}=\frac{21}{29}$
$\sec A=\frac{1}{\cos A}=\frac{29}{21}$
$\tan A=\frac{\text{opposite side}}{\text{adjacent side}}=\frac{40}{42}=\frac{20}{21}$
$\cot A=\frac{1}{\tan A}=\frac{21}{20}$