Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Chapter 5 Test Prep - Review Exercises - Page 560: 32

Answer

$\sin A=\frac{20}{29}$ $\csc A=\frac{29}{20}$ $\cos A=\frac{21}{29}$ $\sec A=\frac{29}{21}$ $\tan A=\frac{20}{21}$ $\cot A=\frac{21}{20}$

Work Step by Step

$\sin A=\frac{\text{opposite side}}{\text{hypotenuse}}=\frac{40}{58}=\frac{20}{29}$ $\csc A=\frac{1}{\sin A}=\frac{29}{20}$ $\cos A=\frac{\text{adjacent side}}{\text{hypotenuse}}=\frac{42}{58}=\frac{21}{29}$ $\sec A=\frac{1}{\cos A}=\frac{29}{21}$ $\tan A=\frac{\text{opposite side}}{\text{adjacent side}}=\frac{40}{42}=\frac{20}{21}$ $\cot A=\frac{1}{\tan A}=\frac{21}{20}$
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