Answer
$\frac{\sqrt 2}{2},-\frac{\sqrt 2}{2},-1,-1,-\sqrt 2,\sqrt 2$
Work Step by Step
1. Given $\theta=-225^\circ=-180^\circ-45^\circ$, we can identify it is in quadrant II with a reference angle $45^\circ$, we have:
2. $sin\theta=sin45^\circ=\frac{\sqrt 2}{2}$
3. $cos\theta=-cos45^\circ=-\frac{\sqrt 2}{2}$
4. $tan\theta=-tan45^\circ=-1$
5. $cot\theta=\frac{1}{tan\theta}=-1$
6. $sec\theta=\frac{1}{cos\theta}=-\sqrt 2$
7. $csc\theta=\frac{1}{sin\theta}=\sqrt 2$
