Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Chapter 5 Test Prep - Review Exercises - Page 560: 37

Answer

$120^\circ, 240^\circ$

Work Step by Step

Given $cos\theta=-\frac{1}{2}$, we can a reference angle $\theta_0=acos(\frac{1}{2})=60^\circ$ and all values in $[0^\circ,360^\circ)$ as $\theta=120^\circ, 240^\circ$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.