Answer
$-\frac{1}{2},\frac{\sqrt 3}{2},-\frac{\sqrt {3}}{3},-\sqrt 3,\frac{2\sqrt 3}{3},-2$
Work Step by Step
1. Given $\theta=-1470^\circ=-4\times360^\circ-30^\circ$, we can identify it is in quadrant IV with a reference angle $30^\circ$, we have:
2. $sin\theta=-sin30^\circ=-\frac{1}{2}$
3. $cos\theta=cos30^\circ=\frac{\sqrt 3}{2}$
4. $tan\theta=-tan30^\circ=-\frac{\sqrt {3}}{3}$
5. $cot\theta=\frac{1}{tan\theta}=-\sqrt 3$
6. $sec\theta=\frac{1}{cos\theta}=\frac{2\sqrt 3}{3}$
7. $csc\theta=\frac{1}{sin\theta}=-2$
