Answer
$\frac{\sqrt 3}{2},-\frac{1}{2},-\sqrt 3,-\frac{\sqrt {3}}{3},-2,\frac{2\sqrt 3}{3}$
Work Step by Step
1. Given $\theta=120^\circ=180^\circ-60^\circ$, we can identify it is in quadrant II with a reference angle $60^\circ$, we have:
2. $sin\theta=sin60^\circ=\frac{\sqrt 3}{2}$
3. $cos\theta=-cos60^\circ=-\frac{1}{2}$
4. $tan\theta=-tan60^\circ=-\sqrt 3$
5. $cot\theta=\frac{1}{tan\theta}=-\frac{\sqrt {3}}{3}$
6. $sec\theta=\frac{1}{cos\theta}=-2$
7. $csc\theta=\frac{1}{sin\theta}=\frac{2\sqrt 3}{3}$
