Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Chapter 5 Test Prep - Review Exercises - Page 560: 29

Answer

$-\frac{3}{5}, \frac{4}{5}, -\frac{3}{4}, -\frac{4}{3}, \frac{5}{4}, -\frac{5}{3}$

Work Step by Step

1. Given $sec\theta=\frac{1}{cos\theta}=\frac{5}{4}$ and $\theta$ in quadrant IV, we have $cos\theta=\frac{4}{5}$. Form a right triangle with sides $\sqrt {5^2-4^2},4,5$ or $3,4,5$, we have: 2. $sin\theta=-\frac{3}{5}$ 3. $cos\theta=\frac{4}{5}$ 4. $tan\theta=-\frac{3}{4}$ 5. $cot\theta=\frac{1}{tan\theta}=-\frac{4}{3}$ 6. $sec\theta=\frac{1}{cos\theta}=\frac{5}{4}$ 7. $csc\theta=\frac{1}{sin\theta}=-\frac{5}{3}$
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