Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 520: 151

Answer

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Work Step by Step

$x^{2}+y^{2}=r^{2}$ Dividing by $y^{2}$, we get $\frac{x^{2}}{y^{2}}+\frac{y^{2}}{y^{2}}=\frac{r^{2}}{y^{2}}$ Or $(\frac{x}{y})^{2}+1=(\frac{r}{y})^{2}$ Knowing that $\frac{x}{y}=\cot\theta$ and $\frac{r}{y}=\csc\theta$, we obtain $1+\cot^{2}\theta=\csc^{2}\theta$
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