Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 520: 150

Answer

$\csc\theta$ and $\cot\theta$ are not defined. $\cos\theta=1$ $\sin\theta=0$ $\sec\theta=1$ $\tan\theta=0$

Work Step by Step

Given $\cos\theta=1$ Recall: $\sin^{2}\theta+\cos^{2}\theta=1$ $\implies 1^{2}+\sin^{2}\theta=1$ Or $\sin^{2}\theta=0\implies \sin\theta=0$ $\csc\theta=\frac{1}{\sin\theta}=\frac{1}{0}=\text{undefined}$ $\sec\theta=\frac{1}{\cos\theta}=\frac{1}{1}=1$ $\tan\theta=\frac{\sin\theta}{\cos\theta}=\frac{0}{1}=0$ $\cot\theta=\frac{\cos\theta}{\sin\theta}=\frac{1}{0}=\text{undefined}$
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