Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 520: 138

Answer

$-0.75$

Work Step by Step

$\sin^{2}\theta+\cos^{2}\theta=1$ $\implies \cos^{2}\theta=1-\sin^{2}\theta$ $=1-(0.6)^{2}=0.64$ $\sec^{2}\theta=\frac{1}{\cos^{2}\theta}=\frac{1}{0.64}=1.5625$ $\tan^{2}\theta=\sec^{2}\theta-1=1.5625-1=0.5625$ $\tan\theta=\pm \sqrt {0.5625}=\pm 0.75$ $\tan\theta$ is negative in the second quadrant. $\implies \tan\theta=-0.75$
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